Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 13 feet and a height of 13 feet. Container B has a radius of 9 feet and a height of 14 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full. To the nearest tenth, what is the percent of Container A that is full after the pumping is complete?

Accepted Solution

Answer:The percentage ≅ 48.4%Step-by-step explanation:* Lets revise how to find the volume of a container shaped cylinder- The volume of any container = area of its base × its height- The base of the cylinder is a circle, area circle = 2 π r,   where r is the length of its radius* In container A:∵ r = 13 feet  , height = 13 feet∴ Its volume = π (13)² × (13) = 2197π feet³* In container B:∵ r = 9 feet  , height = 14 feet∴ Its volume = π (9)² × (14) = 1134π feet³* So to fill container B from container A, you will take from   container A a volume of 1134π feet³- The volume of water left in container A = 2197π - 1134π = 1063π feet³* To find the percentage of the water that is full after pumping   is complete, divide the volume of water left in container A   by the original volume of the container multiplied by 100∴ The percentage = (1063π/2197π) × 100 = 48.3841 ≅ 48.4%